4.) Two charges, it +0.005C charge and a+0.006c charge, are 2 meters apart. a. Galoulate the electric force between them. b. is this force repulsive or altraotive? __ 6.) A small metal sphere with a charge of -2.10times 10^-6C is to the left of another sphere will charge of +1.50times 10^-6C They experience a force of 70,8 N to the left. a. Calculate the distance between them. b. Is this force repulsive or attractive? __ 6.) A helium atom consists of two protons and two electrons that are 7.2times 10^-11 m apart. See Table on the front for the charges of the electrons and protons. a. Calculate the electric force ) A charge of 1.5^ast 10^-7C is placed .128 m from a second charge.If the forco between the charges is 22.6 N what is the magnitude of the second charge? 5.2.0times 10^-2 6.1.78times 10^-7

Let's correct the calculations and explanations for each part of the problems:<br /><br />### 4.) Two charges, \( +0.005 \, \text{C} \) and \( +0.006 \, \text{C} \), are 2 meters apart.<br /><br />#### a. Calculate the electric force between them.<br /><br />Using Coulomb's Law:<br />\[ F = k \frac{|q_1 q_2|}{r^2} \]<br /><br />Where:<br />- \( k = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)<br />- \(1 = +0.005 \, \text{C} \)<br />- \( q_2 = +0.006 \, \text{C} \)<br />- \( r = 2 \, \text{m} \)<br /><br />\[ F = 8.99 \times 10^9 \frac{|0.005 \times 0.006|}{2^2} \]<br />\[ F = 8.99 \times 10^9 \frac{0.00003}{4} \]<br />\[ F = 8.99 \times 10^9 \times 7.5 \times 10^{-5} \]<br />\[ F = 6.7475 \times 10^3 \, \text{N} \]<br /><br />#### b. Is this force repulsive or attractive?<br /><br />Since both charges are positive, the force is repulsive.<br /><br />### 6.) A small metal sphere with a charge of \( -2.10 \times 10^{-6} \, \text{C} \) is to the left of another sphere with a charge of \( +1.50 \times 10^{-6} \, \text{C} \). They experience a force of 70.8 N to the left.<br /><br />#### a. Calculate the distance between them.<br /><br />Using Coulomb's Law:<br />\[ F = k \frac{|q_1 q_2|}{r^2} \]<br /><br />Given:<br />- \( F = 70.8 \, \text{N} \)<br />- \( q_1 = -2.10 \times 10^{-6} \, \text{C} \)<br />- \( q_2 = +1.50 \times 10^{-6} \, \text{C} \)<br /><br />\[ 70.8 = 8.99 \times 10^9 \frac{|-2.10 \times 10^{-6} \times 1.50 \times 10^{-6}|}{r^2} \]<br />\[ 70.8 = 8.99 \times 10^9 \frac{3.15 \times 10^{-12}}{r^2} \]<br />\[ 70.8 = 8.99 \times 10^9 \frac{3.15 \times 10^{-12}}{r^2} \]<br />\[ 70.8 = 28.2415 \times 10^{-3} \frac{1}{r^2} \]<br />\[ 70.8 = 28.2415 \times 10^{-3} \frac{1}{r^2} \]<br />\[ r^2 = \frac{28.2415 \times 10^{-3}}{70.8} \]<br />\[ r^2 = 4.005 \times 10^{-4} \]<br />\[ r = \sqrt{4.005 \times 10^{-4}} \]<br />\[ r \approx 0.0632 \, \text{m} \]<br /><br />#### b. Is this force repulsive or attractive?<br /><br />Since one charge is negative and the other is positive, the force is attractive.<br /><br />### 6.) A helium atom two protons and two electrons that are \( 7.2 \times 10^{-11} \, \text{m} \) apart.<br /><br />#### a. Calculate the electric force.<br /><br />Using Coulomb's Law:<br />\[ F = k \frac{|q_1 q_2|}{r^2} \]<br /><br />Given:<br />- \( k = 8.99 \times 10^9 \, \text{N} \cdot \text{m}^2 / \text{C}^2 \)<br />- \( q_1 = +1.602 \times 10^{-19} \, \text{C} \) (charge of a proton)<br />- \( q_2 = -1.602 \times 10^{-19} \, \text{C} \) (charge of an- \( r = 7.2 \times 10^{-11} \, \text{m} \)<br /><br />\[ F = 8.99 \times 10^9 \frac{|1.602 \times 10^{-19}