Let's consider the combustion of magnesium (Mg) in oxygen to form magnesium oxide (MgO) The balanced chemical equation is: 2Mg+O2arrow 2MgO How many moles of MgO will be formed when 12.0 moles of oxygen gas (O_(2)) are reacted? 12 moles 6 moles 4 moles 24 mole

To determine how many moles of magnesium oxide (MgO) will be formed when 12.0 moles of oxygen gas (O₂) are reacted, we need to use the stoichiometry of the balanced chemical equation:<br /><br />\[ 2Mg + O_2 \rightarrow 2MgO \]<br /><br />From the balanced equation, we see that 1 mole of O₂ produces 2 moles of MgO. Therefore, the ratio of O₂ to MgO is 1:2.<br /><br />Given:<br />- Moles of O₂ = 12.0 moles<br /><br />Using the ratio from the balanced equation:<br />\[ \text{Moles of MgO} = 12.0 \, \text{moles of O}_2 \times \frac{2 \, \text{moles of MgO}}{1 \, \text{mole of O}_2} \]<br /><br />\[ \text{Moles of MgO} = 24.0 \, \text{moles} \]<br /><br />Therefore, 24.0 moles of MgO will be formed when 12.0 moles of oxygen gas (O₂) are reacted. The correct answer is 24 moles.