Which best approximates the relationship between the change In velocity and change in kinetic energy. As the release velocity doubles the kinetic energy of the car also doubles quadruples Increases by more than double but doesn't quadruple increases, but by less than twice as much decreases, becoming half as much

## Step 1<br />The kinetic energy of an object is given by the formula:<br />### \( KE = \frac{1}{2}mv^2 \)<br />where \( m \) is the mass of the object and \( v \) is its velocity.<br /><br />## Step 2<br />From the formula, we can see that the kinetic energy is proportional to the square of the velocity. This means that if the velocity of the object doubles, the kinetic energy will increase by a factor of four, or quadruple.<br /><br />## Step 3<br />However, the problem states that the kinetic energy increases by more than double but doesn't quadruple. This suggests that the velocity of the car is not doubling, but rather increasing by a factor greater than two but less than four.