In Experiment 1, if 60% ethylene glycol had been added to the sample, the freezing point would most likely have been: A A greater than -15^circ C B between -15^circ C and -25^circ C B C between -25^circ C and -35^circ C D less than -35^circ C

To determine the effect of adding ethylene glycol on the freezing point of the sample, we need to understand the concept of freezing point depression.<br /><br />Freezing point depression is a colligative property that describes the decrease in the freezing point of a solution compared to the pure solvent. The extent of freezing point depression depends on the concentration of solute particles in the solution.<br /><br />In this case, the addition of ethylene glycol will increase the concentration of solute particles in the solution, leading to a greater freezing point depression.<br /><br />Given that the original freezing point of the sample is $-15^{\circ }C$, adding $60\%$ ethylene glycol will result in a greater freezing point depression. Therefore, the freezing point of the solution will be lower than $-15^{\circ }C$.<br /><br />Therefore, the correct answer is:<br />D. less than $-35^{\circ }C$