8) 2Na(NO_(3))+2PbOarrow underline (2)Pb(NO_(3))_(2)+underline (1)Na_(2)O Typ __

## Step 1<br />The given chemical equation is \(2Na(NO_{3})+2PbO\rightarrow \underline {2}Pb(NO_{3})_{2}+\underline {1}Na_{2}O\). This equation represents a chemical reaction where Sodium Nitrate (Na(NO3)) and Lead(II) Oxide (PbO) react to form Lead(II) Nitrate (Pb(NO3)2) and Sodium Oxide (Na2O).<br /><br />## Step 2<br />To balance a chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. This is in accordance with the Law of Conservation of Mass, which states that matter cannot be created or destroyed in a chemical reaction.<br /><br />## Step 3<br />Looking at the given equation, we can see that the number of Sodium (Na) and Lead (Pb) atoms are already balanced on both sides of the equation. However, the number of Nitrate (NO3) groups is not balanced.<br /><br />## Step 4<br />To balance the Nitrate groups, we need to multiply the number of Sodium Nitrate (Na(NO3)) molecules by 2, which gives us 4 Nitrate groups on the left side of the equation.<br /><br />## Step 5<br />Similarly, we need to multiply the number of Lead(II) Nitrate (Pb(NO3)2) molecules by 2, which gives us 4 Nitrate groups on the right side of the equation.<br /><br />## Step 6<br />Now, the balanced chemical equation is \(4Na(NO_{3})+2PbO\rightarrow 2Pb(NO_{3})_{2}+2Na_{2}O\).