"The molecule SF_(5)Br has a molecular geometry of an octahedron. (The sulfur central atom does not follow the octet rule). Based on this fact, which region of the molecule would contain the most blue area in a potential map?" A On the Fand S atoms B On the Fatoms C "This molecule would be green, and have a net electronegativity of o" D On the Br atom (D) E ) On the Satom

The correct answer is D) On the Br atom.<br /><br />Explanation:<br />In the molecule $SF_{5}Br$, the central sulfur atom is surrounded by five fluorine atoms and one bromine atom. The molecular geometry of the molecule is an octahedron, which means that the sulfur atom is at the center of an octahedron-shaped arrangement of atoms.<br /><br />The potential map of a molecule represents the distribution of electron density around the atoms in the molecule. In this case, the bromine atom (Br) is the most electronegative atom in the molecule, which means it has the highest tendency to attract electrons towards itself.<br /><br />Therefore, the region of the molecule that would contain the most blue area in the potential map would be on the bromine atom (Br), as it would have the highest electron density and the most negative charge