Given a gas is at 4 atm and 24 L, what is the pressure of the gas when volume changes to 18 L? 5.3 atm 18 atm 53 atm ) 35 atm

## Step 1<br />The problem's Law, which states that the pressure and volume of a gas have an inverse relationship when the temperature is held constant. This can be represented by the formula:<br />### \(P1V1 = P2V2\)<br />where \(P1\) and \(V1\) are the initial pressure and volume, and \(P2\) and \(V2\) are the final pressure and volume.<br /><br />## Step 2<br />In this problem, the initial pressure \(P1\) is 4 atm, the initial volume \(V1\) is 24 L, and the final volume \(V2\) is 18 L. We are asked to find the final pressure \(P2\).<br /><br />## Step 3<br />We can rearrange the formula to solve for \(P2\):<br />### \(P2 = \frac{P1V1}{V2}\)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \(P2 = \frac{4 \, \text{atm} \times 24 \, \text{L}}{18 \, \text{L}}\)<br /><br />## Step 5<br />Calculate the value of \(P2\).