Given a gas is at 23 L and 10 mol, what is the volume of the gas when the number of moles changes to 8 mol? 23.0 L 18.4 L 9.8 L 1.841

## Step 1<br />The problem involves the application of Avogadro's Law, which states that the volume of a gas is directly proportional to the number of moles of the gas, provided the temperature and pressure remain constant. This relationship can be expressed as:<br />### \(V_1/n_1 = V_2/n_2\)<br />where \(V_1\) and \(n_1\) are the initial volume and number of moles, and \(V_2\) and \(n_2\) are the final volume and number of moles.<br /><br />## Step 2<br />In this problem, we are given the initial volume \(V_1 = 23 L\) and the initial number of moles \(n_1 = 10 mol\). We are asked to find the final volume \(V_2\) when the number of moles changes to \(n_2 = 8 mol\).<br /><br />## Step 3<br />We can rearrange the formula to solve for \(V_2\):<br />### \(V_2 = V_1 * (n_2/n_1)\)<br /><br />## Step 4<br />Substitute the given values into the formula:<br />### \(V_2 = 23 L * (8 mol / 10 mol) = 18.4 L\)