Find the zeros of the quadratic function.(Enter your answers as a comma-separated lisi f(x)=6(x-1)^2-96 x= square

To find the zeros of the quadratic function \( f(x) = 6(x-1)^2 - 96 \), we need to solve for \( x \) when \( f(x) = 0 \).<br /><br />Set the function equal to zero:<br />\[ 6(x-1)^2 - 96 = 0 \]<br /><br />Add 96 to both sides:<br />\[ 6(x-1)^2 = 96 \]<br /><br />Divide both sides by 6:<br />\[ (x-1)^2 = 16 \]<br /><br />Take the square root of both sides:<br />\[ x-1 = \pm 4 \]<br /><br />Solve for \( x \):<br />\[ x = 1 + 4 \quad \text{or} \quad x = 1 - 4 \]<br />\[ x = 5 \quad \text{or} \quad x = -3 \]<br /><br />Therefore, the zeros of the quadratic function are:<br />\[ x = 5, -3 \]