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<div class="athena_tag_tk_ques_text_content" data-testid="answer_box_text"><p><strong>Respuesta:</strong></p><p>1</p><p><strong>Explicación:</strong></p><p>Uso de la reglas de los exponentes.<br/>Recordemos:<br/><img align="absmiddle" alt="a^{n} *a^{m} = a^{n+m}" class="athena_tag_latex_mark" id="TexFormula1" src="https://hw-cdn.snapquiz.net/seahk_0116cd9f85f004e2f65be0b4e1f77289.jpg" title="a^{n} *a^{m} = a^{n+m}"/><br/><img align="absmiddle" alt="\frac{a^{n} }{a^{m} } = a^{n-m}" class="athena_tag_latex_mark" id="TexFormula2" src="https://hw-cdn.snapquiz.net/seahk_38286ed1b6626a2805da9b3f7a2ed46e.jpg" title="\frac{a^{n} }{a^{m} } = a^{n-m}"/><br/><img align="absmiddle" alt="(a^{n})^{m} = a^{nm}" class="athena_tag_latex_mark" id="TexFormula3" src="https://hw-cdn.snapquiz.net/seahk_2e73de9a4403df2cd23c33c63f9a0573.jpg" title="(a^{n})^{m} = a^{nm}"/><br/>Solución:<br/><img align="absmiddle" alt="\frac{2^{16}*16^{2} }{8^{8} } = \frac{2^{16}*(2^{4})^{2} }{(2^{3}) ^{8}} = \frac{2^{16}*2^{8} }{2^{24} } = \frac{2^{24} }{2^{24} } = 2^{24-24}= 2^{0}= 1" class="athena_tag_latex_mark" id="TexFormula4" src="https://hw-cdn.snapquiz.net/seahk_ba8df947f0d6a2703fb02c22c8aee64d.jpg" title="\frac{2^{16}*16^{2} }{8^{8} } = \frac{2^{16}*(2^{4})^{2} }{(2^{3}) ^{8}} = \frac{2^{16}*2^{8} }{2^{24} } = \frac{2^{24} }{2^{24} } = 2^{24-24}= 2^{0}= 1"/><br/></p></div>