Stolemometry Practice POSSIBLE POINTS: 12 2C_(7)H_(6)O_(2)+15O_(2)Leftrightarrow 14CO_(2)+6H_(2)O Philly reacted 120g of Benzoic acid with a surplus of Oxygen gas.If the reaction produced 60g of Carbon dioxide what was Philly's percent yield? 45% 50% 20% 78%

To calculate the percent yield, we need to determine the theoretical yield of carbon dioxide (CO2) and then compare it to the actual yield.<br /><br />Given information:<br />- Reaction: $2C_{7}H_{6}O_{2} + 15O_{2} \Leftrightarrow 14CO_{2} + 6H_{2}O$<br />- Philly reacted 120g of benzoic acid (C7H6O2) with a surplus of oxygen gas.<br />- The reaction produced 60g of carbon dioxide (CO2).<br /><br />Step 1: Calculate the molar mass of benzoic acid (C7H6O2).<br />Molar mass of C7H6O2 = 7 × 12.01 + 6 × 1.01 + 2 × 16.00 = 122.12 g/mol<br /><br />Step 2: Calculate the number of moles of benzoic acid (C7H6O2) reacted.<br />Moles of C7H6O2 = 120g / 122.12 g/mol = 0.983 mol<br /><br />Step 3: Calculate the theoretical yield of carbon dioxide (CO2).<br />According to the balanced equation, 2 moles of C7H6O2 produce 14 moles of CO2.<br />Moles of CO2 produced = 0.983 mol C7H6O2 × (14 mol CO2 / 2 mol C7H6O2) = 6.83 mol CO2<br />Molar mass of CO2 = 44.01 g/mol<br />Theoretical yield of CO2 = 6.83 mol × 44.01 g/mol = 300.6g CO2<br /><br />Step 4: Calculate the percent yield.<br />Percent yield = (Actual yield / Theoretical yield) × 100%<br />Percent yield = (60g / 300.6g) × 100% = 20%<br /><br />Therefore, the correct answer is $20\%$.