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PCl_(5)+underline ( )H_(2)Oarrow underline ( )HCl+H_(3)PO_(4) What coefficients would be needed to balance the above equation? 4,5 3,8 2,2 1,6

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PCl_(5)+underline ( )H_(2)Oarrow underline ( )HCl+H_(3)PO_(4)
What coefficients would be needed to balance the above equation?
4,5
3,8
2,2
1,6

PCl_(5)+underline ( )H_(2)Oarrow underline ( )HCl+H_(3)PO_(4) What coefficients would be needed to balance the above equation? 4,5 3,8 2,2 1,6

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Anaélite · Tutor durante 8 años
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To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $PCl_{5} + \underline{\quad}H_{2}O \rightarrow \underline{\quad}HCl + H_{3}PO_{4}$<br /><br />Let's start by balancing the chlorine (Cl) atoms. There are 5 chlorine atoms in $PCl_{5}$, so we need 5 chlorine atoms on the product side. Therefore, we need 5 molecules of $HCl$.<br /><br />Now, let's balance the hydrogen (H) atoms. There are 5 hydrogen atoms in 5 molecules of $HCl$, so we need 5 hydrogen atoms on the reactant side. Therefore, we need 5 molecules of $H_{2}O$.<br /><br />Finally, let's balance the phosphorus (P) atoms. There is 1 phosphorus atom in $PCl_{5}$ and 1 phosphorus atom in $H_{3}PO_{4}$. So, the phosphorus atoms are already balanced.<br /><br />The balanced chemical equation is:<br />$PCl_{5} + 5H_{2}O \rightarrow 5HCl + H_{3}PO_{4}$<br /><br />Therefore, the coefficients needed to balance the equation are 1, 5, 5, and 1.
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