The pressure in a cartie is 198 27^circ C After a long drive the pressure is 225492. What is the temperature of the air in the volume is constant P_(1)=2 T_(1)T_(2) "watch the temperature." ax

To solve this problem, we can use the ideal gas law, which states that the pressure of a gas is directly proportional to its temperature, provided the volume remains constant.<br /><br />Given information:<br />- Initial pressure, P1 = 198 kPa<br />- Initial temperature, T1 = 27°C<br />- Final pressure, P2 = 225 kPa<br /><br />We need to find the final temperature, T2.<br /><br />Using the ideal gas law, we can write the equation as:<br /><br />P1/T1 = P2/T2<br /><br />Substituting the given values, we get:<br /><br />198 kPa / 27°C = 225 kPa / T2<br /><br />Solving for T2, we get:<br /><br />T2 = (225 kPa × 27°C) / 198 kPa<br />T2 = 31.5°C<br /><br />Therefore, the temperature of the air in the cartie after the long drive is 31.5°C.