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Question 12 (1 point) Joe lifts a 5Kg box from a step that is 0.2m high to a shelf that is 1.75m.How much work did Joe accomplish? 43.1 b 85.75 J c 75.95 J d 98.

Problemas

Question 12 (1 point)
Joe lifts a 5Kg box from a step that is 0.2m high to a shelf that is 1.75m.How much work did Joe accomplish?
43.1
b
85.75 J
c
75.95 J
d
98.

Question 12 (1 point) Joe lifts a 5Kg box from a step that is 0.2m high to a shelf that is 1.75m.How much work did Joe accomplish? 43.1 b 85.75 J c 75.95 J d 98.

Solución

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Danielmaestro · Tutor durante 5 años
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The work done by Joe is 85.75 J.

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## Step 1<br />The work done by Joe is calculated using the formula for work, which is the product of the force applied and the distance over which the force is applied. In this case, the force is the weight of the box, and the distance is the height difference between the step and the shelf.<br /><br />### **Work = Force x Distance**<br /><br />## Step 2<br />The weight of the box is calculated by multiplying its mass by the acceleration due to gravity. The mass of the box is 5 kg and the acceleration due to gravity is approximately 9.8 m/s².<br /><br />### **Weight = Mass x Gravity**<br /><br />## Step 3<br />The height difference between the step and the shelf is calculated by subtracting the height of the step from the height of the shelf. The height of the step is 0.2 m and the height of the shelf is 1.75 m.<br /><br />### **Height Difference = Height of Shelf - Height of Step**<br /><br />## Step 4<br />Substitute the calculated values into the formula for work.<br /><br />### **Work = Weight x Height Difference**
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