The following equation represents the reaction between solid aluminum and hydrochloric acid. Balance the equation by filling in the correct coefficients for each substance. boxed (1)Al(s)+boxed (3)HCl(aq)arrow boxed (1)AlCl_(3)(aq)+boxed (3)H_(2)(g) 1/6 A balanced chemical equation shows the same number of each type of atom on both sides of the arrow. We need to balance all three elements (Al, H and C1) to answer this question. + Get another hint (1/6) square

The given chemical equation is:<br />\[ Al(s) + HCl(aq) \rightarrow AlCl_3(aq) + H_2(g) \]<br />To balance the equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />1. Aluminum (Al) is already balanced with 1 atom on both sides.<br />2. Hydrogen (H) has 1 atom on the left side and 2 atoms on the right side. To balance hydrogen, we need to have 2 molecules of HCl on the left side, which gives us 2 hydrogen atoms on the left side.<br />3. Chlorine (Cl) has 1 atom on the left side and 3 atoms on the right side. To balance chlorine, we need to have 3 molecules of HCl on the left side, which gives us 3 chlorine atoms on the left side.<br /><br />After balancing the atoms, the balanced chemical equation is:<br />\[ Al(s) + 3HCl(aq) \rightarrow AlCl_3(aq) + 3H_2(g) \]<br /><br />This equation shows that 1 atom of aluminum reacts with 3 molecules of hydrochloric acid to produce 1 molecule of aluminum chloride and 3 molecules of hydrogen gas. The coefficients are 1 for Al, 3 for HCl, 1 for AlCl3, and 3 for H2, which means that the equation is balanced with the same number of each type of atom on both sides of the arrow.