Question 5 (1 point) The minimum value of x is 12 less than 6 times another number n. Which inequality shows the possible values of x a xleqslant 6n-12 b xgeqslant 12-6n C xgeqslant 6n-12 d d xleqslant 12-6n

The correct inequality that shows the possible values of x is:<br /><br />a) $x \leqslant 6n - 12$<br /><br />Explanation:<br />The problem states that the minimum value of x is 12 less than 6 times another number n. This can be expressed as:<br /><br />$x \leqslant 6n - 12$<br /><br />Therefore, the correct inequality that represents the possible values of x is option a) $x \leqslant 6n - 12$.