5. An object has a kinetic energy of 14 J and a mass of 17 kg, how fast is the object moving?

To find the speed of the object, we can use the formula for kinetic energy:<br /><br />\[ KE = \frac{1}{2}mv^2 \]<br /><br />where:<br />- \( KE \) is the kinetic energy,<br />- \( m \) is the mass,<br />- \( v \) is the velocity.<br /><br />Given:<br />- \( KE = 14 \, \text{J} \)<br />- \( m = 17 \, \text{kg} \)<br /><br />We need to solve for \( v \):<br /><br />\[ 14 = \frac{1}{2} \times 17 \times v^2 \]<br /><br />First, multiply both sides by 2 to get rid of the fraction:<br /><br />\[ 28 = 17 \times v^2 \]<br /><br />Next, divide both sides by 17:<br /><br />\[ v^2 = \frac{28}{17} \]<br /><br />\[ v^2 \approx 1.647 \]<br /><br />Finally, take the square root of both sides to solve for \( v \):<br /><br />\[ v \approx \sqrt{1.647} \]<br /><br />\[ v \approx 1.28 \, \text{m/s} \]<br /><br />So, the object is moving at approximately \( 1.28 \, \text{m/s} \).