What is the percent yield of NaCl if 310 got CuCl_(2) reacts with excess NaNO_(3) to produce 2129 of NaCl Use % Yield=(Actualyield)/(Theorebcalyield)times 100 49.7% 58.4% 63.6% 787%

To calculate the percent yield of NaCl, we need to follow these steps:<br /><br />1. Determine the theoretical yield of NaCl.<br />2. Calculate the percent yield using the given formula.<br /><br />Given information:<br />- 310 g of CuCl2 reacts with excess NaNO3 to produce 2129 g of NaCl.<br /><br />Step 1: Determine the theoretical yield of NaCl.<br />The balanced chemical equation for the reaction is:<br />CuCl2 + 2NaNO3 → 2NaCl + Cu(NO3)2<br /><br />To find the theoretical yield of NaCl, we need to know the molar masses of the reactants and products.<br />Molar mass of CuCl2 = 63.55 g/mol + 2(35.45 g/mol) = 134.45 g/mol<br />Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol<br /><br />Using the stoichiometry of the reaction, we can calculate the theoretical yield of NaCl:<br />Theoretical yield of NaCl = (310 g of CuCl2) × (2 mol of NaCl / 1 mol of CuCl2) × (58.44 g of NaCl / 1 mol of NaCl) = 3628.8 g of NaCl<br /><br />Step 2: Calculate the percent yield of NaCl.<br />Percent yield = (Actual yield / Theoretical yield) × 100<br />Percent yield = (2129 g / 3628.8 g) × 100 = 58.4%<br /><br />Therefore, the percent yield of NaCl is 58.4%.