Problemas
To stop a 29 kg ball going 2.2m/s requires 7.6 Nover 4.4 seconds to stop What momentum of the ball? Round to 1 decimal place. square
Solución
Rubénprofessionell · Tutor durante 6 años
Verificación de expertos
4.4 (244 votos)
Responder
The momentum of the ball is \( p = 29 \, \text{kg} \times 2.2 \, \text{m/s} = 63.8 \, \text{kg m/s} \).
Explicar
## Step 1: <br />First, we need to understand the problem. We are given the mass of the ball (29 kg), its initial velocity (2.2 m/s), and the time it takes to stop (4.4 seconds). We are asked to find the momentum of the ball.<br /><br />## Step 2: <br />Momentum is defined as the product of an object's mass and its velocity. In this case, since the ball comes to a stop, its final velocity is 0 m/s. Therefore, the momentum of the ball is simply the product of its mass and its initial velocity.<br /><br />### The formula for momentum is: <br />### \( p = m \times v \)<br /><br />## Step 3: <br />Substitute the given values into the formula. The mass of the ball (m) is 29 kg and the initial velocity (v) is 2.2 m/s.<br /><br />## Step 4: <br />Calculate the momentum by multiplying the mass and the velocity.
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