A gas is at a temperature of 300 K and occupies a volume of 2 L. If the temperature is increased to 600 K while keeping the pressure constant, what will be the new volume? A. 41 B. 2L C. 3L D. 1L

To solve this problem, we can use Charles's Law, which states that the volume of a gas is directly proportional to its temperature (in Kelvin) when the pressure is constant. The formula for Charles's Law is:<br /><br />\[ \frac{V_1}{T_1} = \frac{V_2}{T_2} \]<br /><br />Where:<br />- \( V_1 \) is the initial volume<br />- \( T_1 \) is the initial temperature<br />- \( V_2 \) is the final volume<br />- \( T_2 \) is the final temperature<br /><br />Given:<br />- \( V_1 = 2 \, \text{L} \)<br />- \( T_1 = 300 \, \text{K} \)<br />- \( T_2 = 600 \, \text{K} \)<br /><br />We need to find \( V_2 \).<br /><br />Rearranging the formula to solve for \( V_2 \):<br /><br />\[ V_2 = V_1 \times \frac{T_2}{T_1} \]<br /><br />Substituting the given values:<br /><br />\[ V_2 = 2 \, \text{L} \times \frac{600 \, \text{K}}{300 \, \text{K}} \]<br /><br />\[ V_2 = 2 \, \text{L} \times 2 \]<br /><br />\[ V_2 = 4 \, \text{L} \]<br /><br />So, the new volume of the gas when the temperature is increased to 600 K while keeping the pressure constant is 4 L.<br /><br />The correct answer is:<br />A. 4L