If you have a 1.10 kg ball traveling in a circle with radius 1.62 mata velocity of 2.24m/s how much is the centripetal force on the ball? square

centripetal force is the force that keeps an object moving in a circular path. It acts inwards towards the center of the circle. The formula for calculating the centripetal force is given by:<br /><br />\[F = \frac{mv^2}{r}\]<br /><br />where:<br />- F is the centripetal force,<br />- m is the mass of the object,<br />- v is the velocity of the object, and<br />- r is the radius of the circular path.<br /><br />In this problem, we are given:<br />- m = 1.10 kg (mass of the ball),<br />- v = 2.24 m/s (velocity of the ball), and<br />- r = 1.62 m (radius of the circular path).<br /><br />Substituting these values into the formula, we get:<br /><br />\[F = \frac{(1.10 \, kg) \times (2.24 \, m/s)^2}{1.62 \, m}\]<br /><br />Calculating the above expression gives us the centripetal force acting on the ball.