Given a gas is at 22 Land 1 mol, what is the volume of the gas when the number of moles changes to 4 mol? Round to one decimal place. square

To solve this problem, we can use the ideal gas law, which states that the volume of a gas is directly proportional to the number of moles of the gas, given that the temperature and pressure remain constant.<br /><br />The ideal gas law can be expressed as:<br /><br />PV = nRT<br /><br />Where:<br />P = Pressure<br />V = Volume<br />n = Number of moles<br />R = Ideal gas constant<br />T = Temperature<br /><br />Given information:<br />- Initial volume (V1) = 22 L<br />- Initial number of moles (n1) = 1 mol<br />- Final number of moles (n2) = 4 mol<br /><br />We need to find the final volume (V2) when the number of moles changes to 4 mol.<br /><br />Using the ideal gas law, we can write the equation for the initial and final states:<br /><br />P1V1 = n1RT<br />P2V2 = n2RT<br /><br />Since the pressure and temperature remain constant, we can divide the two equations:<br /><br />P1V1 / P2V2 = n1 / n2<br /><br />Substituting the given values:<br /><br />22 L / V2 = 1 mol / 4 mol<br /><br />Solving for V2:<br /><br />V2 = (22 L × 4 mol) / 1 mol<br />V2 = 88 L<br /><br />Therefore, the volume of the gas when the number of moles changes to 4 mol is 88.0 L (rounded to one decimal place).