If you have a 033 kg ball traveling in a circle with radius 2.66 m at a velocity of 3.37m/s how much is the centripetal force on the ball? square

The centripetal force is the force that keeps an object moving in a circular path. It acts inwards towards the center of the circle. The formula for calculating the centripetal force is given by:<br /><br />\[F = \frac{mv^2}{r}\]<br /><br />where:<br />- F is the centripetal force,<br />- m is the mass of the object,<br />- v is the velocity of the object, and<br />- r is the radius of the circular path.<br /><br />In this problem, we are given:<br />- m = 0.33 kg (the mass of the ball),<br />- v = 3.37 m/s (the velocity of the ball), and<br />- r = 2.66 m (the radius of the circular path).<br /><br />Substituting these values into the formula, we get:<br /><br />\[F = \frac{(0.33 kg) \times (3.37 m/s)^2}{2.66 m}\]<br /><br />Calculating the above expression gives us the centripetal force on the ball.