What is the Percent composition of N in C_(2)N_(3)F_(2) 15% 40% 23% 72%

To find the percent composition of nitrogen (N) in the compound $C_{2}N_{3}F_{2}$, we need to calculate the molar mass of the compound and then determine the proportion of nitrogen in it.<br /><br />Step 1: Calculate the molar mass of $C_{2}N_{3}F_{2}$.<br />- Carbon (C): 2 atoms × 12.01 g/mol = 24.02 g/mol<br />- Nitrogen (N): 3 atoms × 14.01 g/mol = 42.03 g/mol<br />- Fluorine (F): 2 atoms × 18.998 g/mol = 37.996 g/mol<br /><br />Total molar mass of $C_{2}N_{3}F_{2}$ = 24.02 g/mol + 42.03 g/mol + 37.996 g/mol = 104.046 g/mol<br /><br />Step 2: Calculate the percent composition of nitrogen.<br />Percent composition of N = (Mass of N / Molar mass of $C_{2}N_{3}F_{2}$) × 100%<br />Percent composition of N = (42.03 g/mol / 104.046 g/mol) × 100% ≈ 40.3%<br /><br />Therefore, the percent composition of nitrogen in $C_{2}N_{3}F_{2}$ is approximately 40%.