A student sits on the roof of their house which is 17 meters high. She can launch water balloons (horizontally)from a slingshot at 21m/s. How far will each balloon travel (horizontally)? 39.06 meters 0.06 meters 23.06 meters 43.06 meters

To solve this problem, we need to use the principles of projectile motion.<br /><br />Given information:<br />- The height of the roof is 17 meters.<br />- The initial velocity of the water balloons is 21 m/s (horizontally).<br /><br />Step 1: Calculate the time it takes for the water balloon to fall to the ground.<br />Using the equation of motion for vertical motion:<br />h = (1/2)gt^2<br />Where:<br />h = height (17 m)<br />g = acceleration due to gravity (9.8 m/s^2)<br />t = time<br /><br />Rearranging the equation to solve for time:<br />t = √(2h/g)<br />t = √(2 × 17 m / 9.8 m/s^2)<br />t = 1.85 seconds<br /><br />Step 2: Calculate the horizontal distance traveled by the water balloon.<br />Using the equation of motion for horizontal motion:<br />x = v × t<br />Where:<br />x = horizontal distance<br />v = initial horizontal velocity (21 m/s)<br />t = time (1.85 seconds)<br /><br />x = 21 m/s × 1.85 s<br />x = 39.06 meters<br /><br />Therefore, the correct answer is 39.06 meters.