A player pushes a 250 g hockey puck over frictionless ice with a constant force, causing it to accelerate at 24m/s^2 over a distance of 50.0 cm. a. Find the work done by the hockey player on the puck. I Instructions 250 of 250 words remaining square Apply the concept of the conservation of energy using the work-energy theorem to determine the change in the kinetic energy of the puck. I Instructions

To find the work done by the hockey player on the puck, we can use the formula:<br /><br />Work = Force x Distance<br /><br />Given information:<br />- Mass of the hockey puck = 250 g = 0.25 kg<br />- Acceleration of the puck = 24 m/s²<br />- Distance traveled by the puck = 50.0 cm = 0.5 m<br /><br />Step 1: Calculate the force applied by the player on the puck.<br />Using Newton's second law, we have:<br />Force = Mass x Acceleration<br />Force = 0.25 kg x 24 m/s²<br />Force = 6 N<br /><br />Step 2: Calculate the work done by the player on the puck.<br />Work = Force x Distance<br />Work = 6 N x 0.5 m<br />Work = 3 J<br /><br />Therefore, the work done by the hockey player on the puck is 3 J.<br /><br />To apply the concept of the conservation of energy using the work-energy theorem, we can use the formula:<br /><br />Work = Change in Kinetic Energy<br /><br />Given information:<br />- Work done by the player on the puck = 3 J<br /><br />Step 1: Calculate the change in the kinetic energy of the puck.<br />Work = Change in Kinetic Energy<br />3 J = Change in Kinetic Energy<br /><br />Therefore, the change in the kinetic energy of the puck is 3 J.