Calculate the percent composition of sulfur in H2SO4 a. Step 1: b. Step 2: Solution: __

a. Step 1: Determine the molar mass of $H2SO4$.<br />- The molar mass of hydrogen (H) is approximately 1.01 g/mol.<br />- The molar mass of sulfur (S) is approximately 32.07 g/mol.<br />- The molar mass of oxygen (O) is approximately 16.00 g/mol.<br /><br />To calculate the molar mass of $H2SO4$, we need to add the molar masses of all the atoms in the compound:<br />- Molar mass of $H2SO4$ = (2 * 1.01 g/mol) + (1 * 32.07 g/mol) + (4 * 16.00 g/mol)<br />- Molar mass of $H2SO4$ = 2.02 g/mol + 32.07 g/mol + 64.00 g/mol<br />- Molar mass of $H2SO4$ = 98.09 g/mol<br /><br />b. Step 2: Calculate the percent composition of sulfur in $H2SO4$.<br />- To find the percent composition of sulfur, we need to divide the molar mass of sulfur by the molar mass of $H2SO4$ and then multiply by 100.<br />- Percent composition of sulfur = (Molar mass of sulfur / Molar mass of $H2SO4$) * 100<br />- Percent composition of sulfur = (32.07 g/mol / 98.09 g/mol) * 100<br />- Percent composition of sulfur ≈ 32.65%<br /><br />Solution: The percent composition of sulfur in $H2SO4$ is approximately 32.65%.