Which equation correctly represents the alpha decay of polonium -214 A (}_{84)^214Poarrow _(85)^214Po+_(-1)^0e B (}_{84)^214Po+_(4)^2Hearrow _(90)^216Th C (}_{84)^214Poarrow _(82)^210Pb+_(2)^4He D (}_{84)^214Poarrow _(82)^214Pb+_(2)^0He

The correct answer is C.<br /><br />Alpha decay is a type of radioactive decay in which an atomic nucleus emits an alpha particle (a helium nucleus, ${}_{2}^{4}He and transforms into a new element. In the case of polonium-214 (${}_{84}^{214}Po$), the alpha decay can be represented by the equation:<br /><br />${}_{84}^{214}Po\rightarrow _{82}^{210}Pb+_{2}^{4}He$<br /><br />This equation shows that polonium-214 decays into lead-210 (${}_{82}^{210}Pb$) by emitting an alpha particle. The atomic number decreases by 2, and the mass number decreases by 4, which is consistent with the characteristics of alpha decay.