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11. Solid zinc oxide is added to hydrochloric acid to form zinc chloride in water. How many moles of zinc chloride will be produced when 112 grams of zinc oxide is used? 1.38 mols 3.07 mols 56.0 mols 112 mols

Problemas

11. Solid zinc oxide is added to hydrochloric acid to form zinc chloride in water.
How many moles of zinc chloride will be produced when 112 grams of zinc
oxide is used?
1.38 mols
3.07 mols
56.0 mols
112 mols

11. Solid zinc oxide is added to hydrochloric acid to form zinc chloride in water. How many moles of zinc chloride will be produced when 112 grams of zinc oxide is used? 1.38 mols 3.07 mols 56.0 mols 112 mols

Solución

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Pedroprofessionell · Tutor durante 6 años
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To determine how many moles of zinc chloride will be produced, we need to use the balanced chemical equation for the reaction between zinc oxide (ZnO) and hydrochloric acid (HCl):<br /><br />\[ \text{ZnO} + 2\text{HCl} \rightarrow \text{ZnCl}_2 + \text{H}_2\text{O} \]<br /><br />From the balanced equation, we can see that 1 mole of ZnO reacts with 2 moles of HCl to produce 1 mole of ZnCl\(_2\).<br /><br />First, calculate the number of moles of ZnO in 112 grams:<br /><br />1. Find the molar mass of ZnO:<br /> - Zinc (Zn): approximately 65.38 g/mol<br /> - Oxygen (O): approximately 16.00 g/mol<br /> - Molar mass of ZnO = 65.38 g/mol + 16.00 g/mol = 81.38 g/mol<br /><br />2. Calculate the moles of ZnO:<br /> \[<br /> \text{Moles of ZnO} = \frac{\text{mass}}{\text{molar mass}} = \frac{112 \text{ g}}{81.38 \text{ g/mol}} \approx 1.38 \text{ moles}<br /> \]<br /><br />Since the reaction produces 1 mole of ZnCl\(_2\) for every mole of ZnO used, 1.38 moles of ZnO will produce 1.38 moles of ZnCl\(_2\).<br /><br />Therefore, the correct answer is **1.38 moles**.
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