About how many millimeters did the brass wire stretch at 60^circ C A 0.9 mm B 1.0 mm C 1.1 mm D 1.3 mm

To determine the correct answer, we need to use the formula for linear expansion:<br /><br />\[ \Delta L = L_0 \cdot \alpha \cdot \Delta T \]<br /><br />where:<br />- \(\Delta L\) is the change in length,<br />- \(L_0\) is the original length,<br />- \(\alpha\) is the coefficient of linear expansion for brass,<br />- \(\Delta T\) is the change in temperature.<br /><br />Given:<br />- \(\alpha\) for brass is approximately \(19 \times 10^{-6} \, ^\circ\text{C}^{-1}\),<br />- \(\Delta T = 60^\circ\text{C}\).<br /><br />Assuming the original length \(L_0\) is 1 meter (1000 mm) for simplicity:<br /><br />\[ \Delta L = 1000 \, \text{mm} \times 19 \times 10^{-6} \, ^\circ\text{C}^{-1} \times 60^\circ\text{C} \]<br /><br />\[ \Delta L = 1000 \times 19 \times 10^{-6} \times 60 \]<br /><br />\[ \Delta L = 1.14 \, \text{mm} \]<br /><br />The closest option to this value is:<br /><br />C 1.1 mm