Balance the following chemical equation: underline ( )H3PO4+underline ( )KOHarrow underline ( )K3PO4+underline ( )H2O (1,3,1,3) (3,3,1,1) (1,6,1,4) (2,3,1,3)

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $H_3PO_4 + KOH \rightarrow K_3PO_4 + H_2O$<br /><br />Let's balance the equation step by step:<br /><br />1. Balance the potassium (K) atoms:<br /> - There are 3 potassium atoms on the right side (in $K_3PO_4$).<br /> - To balance the potassium atoms, we need 3 KOH molecules on the left side.<br /> - So, the equation becomes: $H_3PO_4 + 3KOH \rightarrow K_3PO_4 + H_2O$<br /><br />2. Balance the hydrogen (H) atoms:<br /> - There are 3 hydrogen atoms on the left side (in $H_3PO_4$).<br /> - There are 3 hydrogen atoms on the right side (in $H_2O$).<br /> - The hydrogen atoms are already balanced.<br /><br />3. Balance the oxygen (O) atoms:<br /> - There are 4 oxygen atoms on the left side (in $H_3PO_4$).<br /> - There are 4 oxygen atoms on the right side (in $K_3PO_4$).<br /> - The oxygen atoms are already balanced.<br /><br />Therefore, the balanced chemical equation is:<br />$H_3PO_4 + 3KOH \rightarrow K_3PO_4 + 3H_2O$<br /><br />So, the correct answer is $(1, 3, 1, 3)$.