Show all work with your balanced reaction to receive full credit. Na+O_(2)arrow Na_(2)O Al+S_(0)arrow Al_(2)S_(3) Cs+ N_(2)arrow Cs_(3)N 4. Rb+ Parrow Rb_(3)P 5. Rb+ S_(1)arrow Rb_(2)S

## Step 1: Balancing the first reaction<br />The first reaction is between sodium (Na) and oxygen (O2) to form sodium oxide (Na2O). To balance this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />### \(4Na + O_{2} \rightarrow 2Na_{2}O\)<br /><br />## Step 2: Balancing the second reaction<br />The second reaction is between aluminum (Al) and sulfur (S) to form aluminum sulfide (Al2S3). To balance this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />### \(2Al + 3S \rightarrow Al_{2}S_{3}\)<br /><br />## Step 3: Balancing the third reaction<br />The third reaction is between cesium (Cs) and nitrogen (N2) to form cesium nitride (Cs3N). To balance this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />### \(6Cs + N_{2} \rightarrow 2Cs_{3}N\)<br /><br />## Step 4: Balancing the fourth reaction<br />The fourth reaction is between rubidium (Rb) and phosphorus (P) to form rubidium phosphide (Rb3P). To balance this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />### \(6Rb + 2P \rightarrow 2Rb_{3}P\)<br /><br />## Step 5: Balancing the fifth reaction<br />The fifth reaction is between rubidium (Rb) and sulfur (S) to form rubidium sulfide (Rb2S). To balance this reaction, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />### \(2Rb + S \rightarrow Rb_{2}S\)