Problemas

Multiple Choice 1 point 1. Select Mars. Click OK. 2. Set the semi-major axis for Mars to 1.52 AU. 3. Observe how long Mars takes to complete one full orbit. 4. Evaluate the graph and the calculation for orbital period (p). 5. What is the orbital period of Mars when its semi-major axis is 1.52 AU? 1.88 years 1.52 years 1 year 3.54 years
Solución
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Vanessamaestro · Tutor durante 5 años
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Responder
The orbital period of Mars when its semi-major axis is 1.52 AU is approximately 3.54 years.
Explicar
## Step 1<br />The problem involves the calculation of the orbital period of Mars when its semi-major axis is 1.52 AU. The Kepler's Third Law of Planetary Motion is used to solve this problem. The law states that the square of the orbital period (p) of a planet is directly proportional to the cube of the semi-major axis (a) of its orbit. This can be mathematically represented as:<br />### \(p^2 = a^3\)<br />## Step 2<br />In this problem, the semi-major axis (a) is given as 1.52 AU. We need to find the orbital period (p). We can rearrange the Kepler's Third Law to solve for p:<br />### \(p = \sqrt{a^3}\)<br />## Step 3<br />Substitute the given value of a into the formula:<br />### \(p = \sqrt{(1.52)^3}\)<br />## Step 4<br />Calculate the square root of the cube of 1.52. The result is approximately 3.54 years.
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