Read the passage and answer the following question(s) Passage 8728 Directions: The balanced equation shows the reaction of nontic acid and sodium hydroxide. 7.29 milliers (mL) of 0.87 M NoOH reacts completely with 1215 mL of CH_(3)COOH Use this information and the equation to answer any questions that follow. CH_(3)COOH+NaOHarrow HOH+NaCH_(3)COO What is the concentration of acetic acid, in terms of its molarity? 0.384 M 0.756 M 1.044 M 0.522 M

To find the concentration of acetic acid, we need to use the balanced equation and the given information.<br /><br />Given:<br />- Volume of NaOH: 7.29 mL<br />- Molarity of NaOH: 0.87 M<br />- Volume of CH3COOH: 1215 mL<br /><br />Step 1: Calculate the moles of NaOH.<br />Moles of NaOH = Molarity × Volume<br />Moles of NaOH = 0.87 M × 0.00729 L<br />Moles of NaOH = 0.00634 mol<br /><br />Step 2: Use the balanced equation to find the moles of CH3COOH.<br />From the balanced equation, we know that 1 mole of CH3COOH reacts with 1 mole of NaOH.<br />Therefore, moles of CH3COOH = moles of NaOH<br />Moles of CH3COOH = 0.00634 mol<br /><br />Step 3: Calculate the concentration of acetic acid.<br />Concentration of CH3COOH = Moles / Volume<br />Concentration of CH3COOH = 0.00634 mol / 0.1215 L<br />Concentration of CH3COOH = 0.0522 M<br /><br />Therefore, the concentration of acetic acid is 0.0522 M.