00910.0 points Find the density of seawater at a depth where the pressure is 300 atm if the density at the surfnce is 1100kg/m^3 Seawater has a bulk modulus of 2.3times 10^9N/m^2 Bulk modulus is defined to be B=(rho _(0)Delta P)/(Delta rho ) Answer in units of kg/m^3

To find the density of seawater at a depth where the pressure is 300 atm, we can use the bulk modulus formula:<br /><br />$B = \frac{\rho_0 \Delta P}{\Delta \rho}$<br /><br />Given:<br />- Bulk modulus, $B = 2.3 \times 10^9 N/m^2$<br />- Density at the surface, $\rho_0 = 1100 kg/m^3$<br />- Pressure at the depth, $P = 300 atm$<br /><br />First, we need to convert the pressure from atm to Pa:<br />$P = 300 atm \times 101325 Pa/atm = 30397500 Pa$<br /><br />Next, we can rearrange the bulk modulus formula to solve for the change in density, $\Delta \rho$:<br />$\Delta \rho = \frac{\rho_0 \Delta P}{B}$<br /><br />Substituting the given values:<br />$\Delta \rho = \frac{1100 kg/m^3 \times 30397500 Pa}{2.3 \times 10^9 N/m^2}$<br />$\Delta \rho = 137.5 kg/m^3$<br /><br />Finally, we can find the density of seawater at the depth by adding the change in density to the surface density:<br />$\rho = \rho_0 + \Delta \rho$<br />$\rho = 1100 kg/m^3 + 137.5 kg/m^3$<br />$\rho = 1237.5 kg/m^3$<br /><br />Therefore, the density of seawater at a depth where the pressure is 300 atm is 1237.5 kg/m^3.