Problemas

Multiple Choice 20 points A container holds 50.0 ml of nitrogen at 25 degrees Celslus and a pressure of 736 mm Hg what will be its volume if the temperature increases to 60 degrees Celslus? 25.0 mL 55.9 mL 20.8 mL 70.0 mL
Solución

Carlaexperto · Tutor durante 3 años

4.4 (211 votos)
Responder
To solve this problem, we can use the ideal gas law, which states that the pressure, volume, and temperature of a gas are related by the equation:<br /><br />PV = nRT<br /><br />where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.<br /><br />First, we need to convert the temperature from Celsius to Kelvin by adding 273.15 to the Celsius temperature:<br /><br />T1 = 25°C + 273.15 = 298.15 K<br />T2 = 60°C + 273.15 = 333.15 K<br /><br />Next, we can use the ideal gas law to find the volume of the gas at the new temperature:<br /><br />V1 = nRT1/P<br />V2 = nRT2/P<br /><br />Since the number of moles and the pressure remain constant, we can simplify the equation to:<br /><br />V1/T1 = V2/T2<br /><br />Substituting the given values, we get:<br /><br />50.0 mL / 298.15 K = V2 / 333.15 K<br /><br />Solving for V2, we get:<br /><br />V2 = 50.0 mL * 333.15 K / 298.15 K = 55.9 mL<br /><br />Therefore, the volume of the gas at 60°C will be 55.9 mL.
Haz clic para calificar: