What is the mass of a piece of copper that displaces 3.0 ml of water and has a density of 9.0g/cm3 mass=densitytimes volume mass=[?]g

To find the mass of the piece of copper, you can use the formula:<br /><br />\[ \text{mass} = \text{density} \times \text{volume} \]<br /><br />Given:<br />- Density of copper = \(9.0 \, \text{g/cm}^3\)<br />- Volume displaced = \(3.0 \, \text{mL}\)<br /><br />Since \(1 \, \text{mL} = 1 \, \text{cm}^3\), the volume is also \(3.0 \, \text{cm}^3\).<br /><br />Now, calculate the mass:<br /><br />\[ \text{mass} = 9.0 \, \text{g/cm}^3 \times 3.0 \, \text{cm}^3 = 27.0 \, \text{g} \]<br /><br />So, the mass of the piece of copper is 27.0 grams.