Ammonium hydrogen phosphate ((NH_(4))_(2)HPO_(4)) a common fertilizer, is made by reacting phosphoric acid (H_(3)PO_(4)) with ammonia according to the following reaction. 2NH_(3)+H_(3)PO_(4)arrow (NH_(4))_(2)HPO_(4) What is the ratio of NH_(3)toH_(3)PO_(4) NH_(3):H_(3)PO_(4)=2:1 √ comman How many moles of ammonia are needed to completely with 3 moles of phosphoric acid? square

To determine how many moles of ammonia are needed to completely react with 3 moles of phosphoric acid, we need to use the stoichiometric relationship from the balanced chemical equation.<br /><br />The balanced chemical equation is:<br />\[ 2NH_3 + H_3PO_4 \rightarrow (NH_4)_2HPO_4 \]<br /><br />From the equation, we see that 2 moles of ammonia (NH_3) are required to react with 1 mole of phosphoric acid (H_3PO_4).<br /><br />Given that we have 3 moles of phosphoric acid, we can set up a proportion to find the moles of ammonia needed:<br /><br />\[ \frac{2 \text{ moles of } NH_3}{1 \text{ mole of } H_3PO_4} = \frac{x \text{ moles of } NH_3}{3 \text{ moles of } H_3PO_4} \]<br /><br />Solving for \( x \):<br /><br />\[ x = 3 \text{ moles of } H_3PO_4 \times \frac{2 \text{ moles of } NH_3}{1 \text{ mole of } H_3PO_4} \]<br /><br />\[ x = 6 \text{ moles of } NH_3 \]<br /><br />Therefore, 6 moles of ammonia are needed to completely react with 3 moles of phosphoric acid.