Pagina de inicio
/
Química
/
(e) If there are 6.54times 10^23 particles of lithium chloride, how many moles are present in the sample? 1.09mol

Problemas

(e) If there are 6.54times 10^23 particles of lithium chloride, how many moles are present in the sample? 1.09mol

(e) If there are 6.54times 10^23 particles of lithium chloride, how many moles are present in the sample? 1.09mol

Solución

avatar
Catalinaveterano · Tutor durante 12 años
expert verifiedVerificación de expertos
4.1 (157 votos)

Responder

1.09 moles

Explicar

The question is asking us to find the number of moles in a sample of lithium chloride, given the number of particles. We know that one mole of any substance contains Avogadro's number of particles, which is $6.022 \times 10^{23}$. So, to find the number of moles, we need to divide the given number of particles by Avogadro's number. <br /><br />So, the calculation would be: <br /><br />\[\frac{6.54 \times 10^{23}}{6.022 \times 10^{23}} = 1.09\]<br /><br />So, the sample contains approximately 1.09 moles of lithium chloride.
Haz clic para calificar: