¿cual es la longitud de un péndulo simple? si su periodo de oscilacion es de 1.5 segundo y la gravedad es de 10 m/s²?​

<div class="athena_tag_tk_ques_text_content" data-testid="answer_box_text"><h2>La longitud del péndulo es de 0.57 metros</h2><p></p><h3><u>Movimiento Pendular</u></h3><p>El <strong>movimiento</strong> que <strong>realiza</strong> el <strong>péndulo simple</strong>, es una <strong>forma</strong> del <u><strong>Movimiento Armónico Simple</strong></u>.</p><p>Un <strong>péndulo</strong> es un<strong> instrumento constituido</strong> por un <strong>cuerpo con peso</strong> que se halla <strong>suspendido en un punto sobre</strong> un <strong>eje horizontal</strong> por <strong>medio</strong> de un <strong>hilo</strong> de <em>masa no considerada</em> y<em><strong> realiza movimientos de un lado a otro</strong></em>.</p><p>Cuando <strong>se aparta</strong> a un <strong>péndulo</strong> de su <strong>posición de equilibrio</strong> y luego <strong>se lo suelta</strong> este <strong>oscila a uno y otro lado</strong> del mismo por <strong>efecto</strong> de su propio <strong>peso</strong>.</p><p><strong>Al movimiento de ida y vuelta</strong> se lo conoce como <u><strong>oscilación</strong></u>.</p><p><strong>El tiempo que tarda en dar una oscilación</strong> se lo llama <u><strong>período</strong></u>.</p><p>Luego al <strong>número </strong>de<strong> oscilaciones ejecutadas </strong>en la <strong>unidad de tiempo</strong> se la denomina <u><strong>frecuencia</strong></u>.</p><p></p><p><strong>Datos:</strong></p><p><img align="absmiddle" alt="\bold{ T} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Per\'iodo de Oscilaci\'on}\ \ \ \ \bold{1.5 \ s}" class="athena_tag_latex_mark" id="TexFormula1" src="https://hw-cdn.snapquiz.net/seahk_b6add653e159008236b29ef05652cf31.jpg" title="\bold{ T} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Per\'iodo de Oscilaci\'on}\ \ \ \ \bold{1.5 \ s}"/></p><p><img align="absmiddle" alt="\bold{ g} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Valor de la aceleraci\'on gravitatoria}\ \ \ \ \bold{10 \ \frac{m}{s^{2} }}" class="athena_tag_latex_mark" id="TexFormula2" src="https://hw-cdn.snapquiz.net/seahk_fdf2faa476936c84b049cafc4e771205.jpg" title="\bold{ g} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Valor de la aceleraci\'on gravitatoria}\ \ \ \ \bold{10 \ \frac{m}{s^{2} }}"/></p><p></p><h3><u>La ecuación para hallar el período está dada por:</u></h3><p><img align="absmiddle" alt="\large\boxed {\bold { T =2\pi \sqrt{ \frac{L }{g } }} }" class="athena_tag_latex_mark" id="TexFormula3" src="https://hw-cdn.snapquiz.net/seahk_f6f5452c1e450a11416d760108ec769a.jpg" title="\large\boxed {\bold { T =2\pi \sqrt{ \frac{L }{g } }} }"/></p><p><strong>Donde</strong></p><p><img align="absmiddle" alt="\bold{ T} \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Per\'iodo}" class="athena_tag_latex_mark" id="TexFormula4" src="https://hw-cdn.snapquiz.net/seahk_c2eeebe068e51e07e75d5b058958042a.jpg" title="\bold{ T} \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Per\'iodo}"/></p><p><img align="absmiddle" alt="\bold{ L} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Longitud del p\'endulo}" class="athena_tag_latex_mark" id="TexFormula5" src="https://hw-cdn.snapquiz.net/seahk_bd4687e4e5da7c5b249c32d4ba72aef6.jpg" title="\bold{ L} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Longitud del p\'endulo}"/></p><p><img align="absmiddle" alt="\bold{ g} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Valor de la aceleraci\'on gravitatoria}" class="athena_tag_latex_mark" id="TexFormula6" src="https://hw-cdn.snapquiz.net/seahk_c289cfae639532e5a311e3b4dd1e0ca2.jpg" title="\bold{ g} \ \ \ \ \ \ \ \ \ \ \ \ \ \large\textsf{Valor de la aceleraci\'on gravitatoria}"/></p><p><img align="absmiddle" alt="\large\textsf{Donde despejaremos la Longitud (L)}" class="athena_tag_latex_mark" id="TexFormula7" src="https://hw-cdn.snapquiz.net/seahk_ea4ca6a29d72860d84478a7d117e7e2c.jpg" title="\large\textsf{Donde despejaremos la Longitud (L)}"/></p><p><img align="absmiddle" alt="\textsf{Realizamos un paso a paso del despeje de la variable L}" class="athena_tag_latex_mark" id="TexFormula8" src="https://hw-cdn.snapquiz.net/seahk_737b9dc2a2e85be56eca9472f5918400.jpg" title="\textsf{Realizamos un paso a paso del despeje de la variable L}"/></p><p><img align="absmiddle" alt="\large\boxed {\bold { T =2\pi \sqrt{ \frac{L }{g } }} }" class="athena_tag_latex_mark" id="TexFormula9" src="https://hw-cdn.snapquiz.net/seahk_f6f5452c1e450a11416d760108ec769a.jpg" title="\large\boxed {\bold { T =2\pi \sqrt{ \frac{L }{g } }} }"/></p><p><img align="absmiddle" alt="\boxed {\bold { \frac{T}{2\pi } = \sqrt{ \frac{L }{g } }} }" class="athena_tag_latex_mark" id="TexFormula10" src="https://hw-cdn.snapquiz.net/seahk_474469bd93b16bc62a8647c51966aa63.jpg" title="\boxed {\bold { \frac{T}{2\pi } = \sqrt{ \frac{L }{g } }} }"/></p><p><img align="absmiddle" alt="\boxed {\bold {\left( \frac{T}{2\pi }\right )^{2} = \left(\sqrt{ \frac{L }{g } }\right)^{2}} }" class="athena_tag_latex_mark" id="TexFormula11" src="https://hw-cdn.snapquiz.net/seahk_36c2794e74954665db662dc4bc4b42a5.jpg" title="\boxed {\bold {\left( \frac{T}{2\pi }\right )^{2} = \left(\sqrt{ \frac{L }{g } }\right)^{2}} }"/></p><p><img align="absmiddle" alt="\boxed {\bold {\frac{T^{2} }{4\pi^{2} } = \frac{L }{g } } }" class="athena_tag_latex_mark" id="TexFormula12" src="https://hw-cdn.snapquiz.net/seahk_acb85bc1461ae9663f2eab2d84548ca5.jpg" title="\boxed {\bold {\frac{T^{2} }{4\pi^{2} } = \frac{L }{g } } }"/></p><p><img align="absmiddle" alt="\boxed {\bold {T^{2}\ . \ g = 4\pi^{2} \ . \ L } }" class="athena_tag_latex_mark" id="TexFormula13" src="https://hw-cdn.snapquiz.net/seahk_4a4b18d971a0a2ec45ea45d295a1fb7e.jpg" title="\boxed {\bold {T^{2}\ . \ g = 4\pi^{2} \ . \ L } }"/></p><p><img align="absmiddle" alt="\boxed {\bold {4\pi^{2} \ . \ L= T^{2} \ . \ g } }" class="athena_tag_latex_mark" id="TexFormula14" src="https://hw-cdn.snapquiz.net/seahk_f83565319b43cd619621006da5155aef.jpg" title="\boxed {\bold {4\pi^{2} \ . \ L= T^{2} \ . \ g } }"/></p><p><img align="absmiddle" alt="\large\boxed {\bold { L = \frac{ T^{2} \ . \ g }{ 4\pi^{2} } } }" class="athena_tag_latex_mark" id="TexFormula15" src="https://hw-cdn.snapquiz.net/seahk_c431c6f65b1ee62ce0e043322ca7cc47.jpg" title="\large\boxed {\bold { L = \frac{ T^{2} \ . \ g }{ 4\pi^{2} } } }"/></p><h3>Ya despejada la variable L</h3><h3><u>Determinamos la longitud del péndulo</u></h3><p><img align="absmiddle" alt="\large\boxed {\bold { L = \frac{ T^{2} \ . \ g }{ 4\pi^{2} } } }" class="athena_tag_latex_mark" id="TexFormula16" src="https://hw-cdn.snapquiz.net/seahk_c431c6f65b1ee62ce0e043322ca7cc47.jpg" title="\large\boxed {\bold { L = \frac{ T^{2} \ . \ g }{ 4\pi^{2} } } }"/></p><p><img align="absmiddle" alt="\large\textsf{Reemplazamos valores y resolvemos}" class="athena_tag_latex_mark" id="TexFormula17" src="https://hw-cdn.snapquiz.net/seahk_7da24b12ed6189e6bb8c44aeddff29aa.jpg" title="\large\textsf{Reemplazamos valores y resolvemos}"/></p><p><img align="absmiddle" alt="\boxed {\bold { L = \frac{ (1.5 \ s)^{2} \ . \ 10 \ \frac{m}{s^{2} } }{ 4\pi^{2} } } }" class="athena_tag_latex_mark" id="TexFormula18" src="https://hw-cdn.snapquiz.net/seahk_0dc921de62b4515363c14d631958963b.jpg" title="\boxed {\bold { L = \frac{ (1.5 \ s)^{2} \ . \ 10 \ \frac{m}{s^{2} } }{ 4\pi^{2} } } }"/></p><p><img align="absmiddle" alt="\boxed {\bold { L = \frac{ 2.25 \not s^{2} \ . \ 10 \ \frac{m}{\not s^{2} } }{ 4\pi^{2} } } }" class="athena_tag_latex_mark" id="TexFormula19" src="https://hw-cdn.snapquiz.net/seahk_ea2773c55b2b6eb2375eaca790138754.jpg" title="\boxed {\bold { L = \frac{ 2.25 \not s^{2} \ . \ 10 \ \frac{m}{\not s^{2} } }{ 4\pi^{2} } } }"/></p><p><img align="absmiddle" alt="\boxed {\bold { L = \frac{ 22.5 \ m }{ 4\pi^{2} } } }" class="athena_tag_latex_mark" id="TexFormula20" src="https://hw-cdn.snapquiz.net/seahk_7e12b4d05629cb56cea19070424bc5f8.jpg" title="\boxed {\bold { L = \frac{ 22.5 \ m }{ 4\pi^{2} } } }"/></p><p><img align="absmiddle" alt="\boxed {\bold { L = \frac{ 22.5 \ m }{ 39.478417604357 } } }" class="athena_tag_latex_mark" id="TexFormula21" src="https://hw-cdn.snapquiz.net/seahk_b6fb4f11743715abfe7c1680f986661f.jpg" title="\boxed {\bold { L = \frac{ 22.5 \ m }{ 39.478417604357 } } }"/></p><p><img align="absmiddle" alt="\boxed {\bold { L = 0.5699\ metros } }" class="athena_tag_latex_mark" id="TexFormula22" src="https://hw-cdn.snapquiz.net/seahk_05370ef4e45234a6bcf62d70f3af2e7a.jpg" title="\boxed {\bold { L = 0.5699\ metros } }"/></p><p><img align="absmiddle" alt="\large\boxed {\bold { L = 0.57\ metros } }" class="athena_tag_latex_mark" id="TexFormula23" src="https://hw-cdn.snapquiz.net/seahk_8861951bfafb3c6cc3ca12010d748184.jpg" title="\large\boxed {\bold { L = 0.57\ metros } }"/></p><h3><u>La longitud del péndulo es de 0.57 metros</u></h3></div>