Balance the following equation: square C_(6)H_(12)+square O_(2)arrow square H_(2)O+square CO_(2)

To balance the chemical equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation.<br /><br />Given equation: $C_{6}H_{12} + O_{2} \rightarrow H_{2}O + CO_{2}$<br /><br />Step 1: Balance the carbon atoms.<br />There are 6 carbon atoms in $C_{6}H_{12}$, so we need 6 $CO_{2}$ molecules on the product side to balance the carbon atoms.<br /><br />$C_{6}H_{12} + O_{2} \rightarrow H_{2}O + 6CO_{2}$<br /><br />Step 2: Balance the hydrogen atoms.<br />There are 12 hydrogen atoms in $C_{6}H_{12}$, so we need 6 $H_{2}O$ molecules on the product side to balance the hydrogen atoms.<br /><br />$C_{6}H_{12} + O_{2} \rightarrow 6H_{2}O + 6CO_{2}$<br /><br />Step 3: Balance the oxygen atoms.<br />On the reactant side, we have 2 oxygen atoms in $O_{2}$. On the product side, we have 6 oxygen atoms in $6H_{2}O$ and 12 oxygen atoms in $6CO_{2}$, making a total of 18 oxygen atoms.<br /><br />To balance the oxygen atoms, we need 9 $O_{2}$ molecules on the reactant side.<br /><br />$C_{6}H_{12} + 9O_{2} \rightarrow 6H_{2}O + 6CO_{2}$<br /><br />Therefore, the balanced chemical equation is:<br /><br />$C_{6}H_{12} + 9O_{2} \rightarrow 6H_{2}O + 6CO_{2}$