Question 11 (1 point) A force 50N acts on a stationary object for 3 secs. If the mass of the object is 25 kg what is the change in velocity of the object? p=mv J=Ft=mDelta v m_(1)v_(1i)+m_(2)v_(2i)=m_(1)v_(1f)+m_(2)v_(2f) a 6m/s b 0.667m/s 3750m/s d 150m/s

To solve this problem, we need to use the formula for impulse and momentum.<br /><br />Given information:<br />- Force (F) = 50 N<br />- Time (t) = 3 s<br />- Mass (m) = 25 kg<br /><br />Step 1: Calculate the impulse (J) applied to the object.<br />Impulse (J) = Force (F) × Time (t)<br />J = 50 N × 3 s = 150 N·s<br /><br />Step 2: Use the impulse-momentum theorem to find the change in velocity (Δv).<br />Impulse (J) = Change in momentum (Δp)<br />J = m × Δv<br />150 N·s = 25 kg × Δv<br />Δv = 150 N·s / 25 kg = 6 m/s<br /><br />Therefore, the change in velocity of the object is 6 m/s.<br /><br />The correct answer is a) 6 m/s.