2Fe_(2)O_(3)+Carrow Fe+3CO_(2) You add 28 grams of carbon. You find the actual yield to be 181.2 grams of CO_(2) What is the percent yield of C (Hint: calculate theoretical yield of CO_(2) first) 58.83% 308% 6435% 15.5

To calculate the percent yield of carbon (C), we first need to determine the theoretical yield of carbon dioxide (CO2) and then use it to find the percent yield of carbon.<br /><br />Given information:<br />- Balanced chemical equation: $2Fe_{2}O_{3} + C \rightarrow Fe + 3CO_{2}$<br />- Actual yield of CO2: 181.2 grams<br />- Mass of carbon added: 28 grams<br /><br />Step 1: Calculate the theoretical yield of CO2.<br />Molar mass of CO2 = 44.01 g/mol<br />Moles of CO2 = 181.2 g / 44.01 g/mol = 4.13 mol<br />Theoretical yield of CO2 = 4.13 mol × 44.01 g/mol = 181.2 g<br /><br />Step 2: Calculate the percent yield of carbon (C).<br />Moles of carbon = 28 g / 12.01 g/mol = 2.33 mol<br />Theoretical yield of carbon = 2.33 mol × 12.01 g/mol = 28 g<br />Percent yield of carbon = (Actual yield of carbon / Theoretical yield of carbon) × 100%<br />Percent yield of carbon = (28 g / 28 g) × 100% = 100%<br /><br />Therefore, the correct answer is 100%.