POSSIBLE POINTS: 6.2 A ball of mass 0.5 kg, initially at rest, acquires a speed of 4m/s immediately after being kicked by a force of strength 20 N. For how lor did this force act on the ball? 0.1 s 0.01 s 0.2 s 1s D 0.02 s

To solve this problem, we can use the impulse-momentum theorem, which states that the impulse experienced by an object is equal to the change in momentum of the object.<br /><br />Given information:<br />- Mass of the ball, m = 0.5 kg<br />- Initial velocity of the ball, v_initial = 0 m/s (at rest)<br />- Final velocity of the ball, v_final = 4 m/s<br />- Force applied on the ball, F = 20 N<br /><br />Step 1: Calculate the change in momentum of the ball.<br />Change in momentum = Final momentum - Initial momentum<br />Final momentum = m × v_final = 0.5 kg × 4 m/s = 2 kg·m/s<br />Initial momentum = m × v_initial = 0.5 kg × 0 m/s = 0 kg·m/s<br />Change in momentum = 2 kg·m/s - 0 kg·m/s = 2 kg·m/s<br /><br />Step 2: Calculate the impulse experienced by the ball.<br />Impulse = Change in momentum = 2 kg·m/s<br /><br />Step 3: Calculate the time duration for which the force acted on the ball.<br />Impulse = Force × Time<br />Time = Impulse / Force<br />Time = 2 kg·m/s / 20 N = 0.1 s<br /><br />Therefore, the force acted on the ball for 0.1 s.<br /><br />The correct answer is 0.1 s.