Vertex Form to Standard Form 1. Write the squared parenthesis as two parentheses multiplied together. 2. Multiply the coefficient the parentheses. 3. Expand the two parentheses. 4. Simplify and be sure it is in order of descending powers of x. y=4(x-3)^2-7

## Step 1: Write the squared parenthesis as two parentheses multiplied together.<br />The given equation is \(y=4(x-3)^{2}-7\). The squared parenthesis \((x-3)^{2}\) can be written as \((x-3)(x-3)\).<br /><br />## Step 2: Multiply the coefficient with the parentheses.<br />The coefficient in the equation is 4. We multiply this with the parentheses \((x-3)(x-3)\) to get \(4(x-3)(x-3)\).<br /><br />## Step 3: Expand the two parentheses.<br />We expand the parentheses \((x-3)(x-3)\) to get \(x^2 - 6x + 9\). Multiplying this with the coefficient 4, we get \(4x^2 - 24x + 36\).<br /><br />## Step 4: Simplify and be sure it is in order of descending powers of x.<br />The equation \(4x^2 - 24x + 36\) is already in descending order of powers of x. Therefore, the standard form of the given equation is \(y = 4x^2 - 24x + 29\).