How many moles are in 432 g of Ba(NO_(3))_(2) 3.25 0.237 0.605 1.65 113,000

To find the number of moles in 432 g of $Ba(NO_{3})_{2}$, we need to use the formula:<br /><br />Number of moles = Mass (in grams) / Molar mass<br /><br />First, let's calculate the molar mass of $Ba(NO_{3})_{2}$:<br /><br />Molar mass of $Ba(NO_{3})_{2}$ = Molar mass of Ba + 2 * Molar mass of N + 6 * Molar mass of O<br />= 137.33 g/mol + 2 * 14.01 g/mol + 6 * 16.00 g/mol<br />= 261.34 g/mol<br /><br />Now, we can calculate the number of moles:<br /><br />Number of moles = 432 g / 261.34 g/mol<br />= 1.65 moles<br /><br />Therefore, there are 1.65 moles in 432 g of $Ba(NO_{3})_{2}$.