6. An object with 500 electrons in placed next to an object with 500 protons and experiences a force of 5N. How far apart are the two objects? 7. How much charge does 1,200 electrons have? Show work. 8. How many electrons were gained or lost by a 4.5 milliC charge? Show work. 9. How does the electric force change? a. If one of the charges is tripled? b. If the distance doubles?

## Step 1:<br />For question 6, we are given that the force between two objects is 5N. According to Coulomb's Law, the force between two charges is given by the formula:<br />### \(F = k \frac{q1*q2}{r^2}\)<br />where \(F\) is the force, \(k\) is Coulomb's constant, \(q1\) and \(q2\) are the charges, and \(r\) is the distance between the charges.<br /><br />## Step 2:<br />For question 7, we need to find the total charge of 1,200 electrons. The charge of one electron is \(-1.6 \times 10^{-19}\) C. Therefore, the total charge is given by:<br />### \(Q = n \times e\)<br />where \(Q\) is the total charge, \(n\) is the number of electrons, and \(e\) is the charge of one electron.<br /><br />## Step 3:<br />For question 8, we need to find the number of electrons corresponding to a charge of 4.5mC. The charge of one electron is \(-1.6 \times 10^{-19}\) C. Therefore, the number of electrons is given by:<br />### \(n = \frac{Q}{e}\)<br />where \(n\) is the number of electrons, \(Q\) is the charge, and \(e\) is the charge of one electron.<br /><br />## Step 4:<br />For question 9, we need to understand how the electric force changes when the charge or distance is altered.