V_(1)=(M_(2)V_(2))/(M_(1)) V_(1)=underline (square )times square square V_(1)=square : 12M : 0.50M : 6.01 : 0.25 L : 0.75 L : 3,01

To solve for \( V_1 \) in the equation \( V_1 = \frac{M_2 V_2}{M_1} \), we need to identify the values of \( M_1 \), \( M_2 \), and \( V_2 \) from the given options.<br /><br />Given:<br />- \( M_1 = 12M \)<br />- \( M_2 = 0.50M \)<br />- \( V_2 = 6.01 \, \text{L} \)<br /><br />We need to find \( V_1 \) in terms of the given values.<br /><br />Substitute the given values into the equation:<br /><br />\[ V_1 = \frac{M_2 V_2}{M_1} \]<br /><br />\[ V_1 = \frac{(0.50M) \times (6.01 \, \text{L})}{12M} \]<br /><br />Now, simplify the expression:<br /><br />\[ V_1 = \frac{0.50 \times 6.01 \, \text{L}}{12} \]<br /><br />\[ V_1 = \frac{3.005 \, \text{L}}{12} \]<br /><br />\[ V_1 = 0.2504167 \, \text{L} \]<br /><br />So, the value of \( V_1 \) is approximately \( 0.25 \, \text{L} \).<br /><br />Therefore, the correct answer is:<br /><br />\[ V_1 = 0.25 \, \text{L} \]