13)What mass of the following chemicals is needed? a) 4.0 liters of a 20 M sodium nitrate solution (NaNO))

## Step 1<br />The problem involves calculating the mass of a sodium nitrate (NaNO3) solution. The molarity (M) of a solution is defined as the number of moles of solute per liter of solution. In this case, the molarity of the sodium nitrate solution is given as 20M, which means there are 20 moles of sodium nitrate per liter of solution.<br /><br />## Step 2<br />The molar mass of sodium nitrate (NaNO3) is calculated by adding the atomic masses of sodium (Na), nitrogen (N), and oxygen (O). The atomic masses of these elements are approximately 23, 14, and 16 respectively. Therefore, the molar mass of sodium nitrate is \(23 + 14 + (16 \times 3) = 85\) g/mol.<br /><br />## Step 3<br />The total mass of sodium nitrate in the solution can be calculated by multiplying the molarity of the solution by the volume of the solution and the molar mass of sodium nitrate. This is represented by the formula:<br /><br />### \(Mass = Molarity \times Volume \times Molar\, Mass\)<br /><br />## Step 4<br />Substituting the given values into the formula, we get:<br /><br />### \(Mass = 20\, moles/L \times 4.0\, L \times 85\, g/mol = 6800\, g\)