Question 2 (2 points) How much 0.075 M NaCl solution can be made by diluting 450 ml of 9.0 MNaCl? __ ml What is the final volume in LITERS? __ L Blank 1 square Blank 2 square

To solve this problem, we can use the dilution formula:<br /><br />C1 × V1 = C2 × V2<br /><br />Where:<br />- C1 is the initial concentration of the solution (9.0 M)<br />- V1 is the initial volume of the solution (450 mL)<br />- C2 is the final concentration of the solution (0.075 M)<br />- V2 is the final volume of the solution (unknown)<br /><br />Rearranging the formula to solve for V2:<br /><br />V2 = (C1 × V1) / C2<br /><br />Substituting the given values:<br /><br />V2 = (9.0 M × 450 mL) / 0.075 M<br />V2 = 5400 mL<br /><br />Therefore, the final volume of the 0.075 M NaCl solution that can be made by diluting 450 mL of 9.0 M NaCl is 5400 mL.<br /><br />To convert the final volume to liters, we can divide by 1000:<br /><br />V2 = 5400 mL / 1000 = 5.4 L<br /><br />So, the final volume in liters is 5.4 L.